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112n^2-63=0
a = 112; b = 0; c = -63;
Δ = b2-4ac
Δ = 02-4·112·(-63)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28224}=168$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*112}=\frac{-168}{224} =-3/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*112}=\frac{168}{224} =3/4 $
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